You take v^2/a = r for the radius of the turn; in a coordinated turn a = g tan (aob) and the time taken to turn 180 degrees is pi * r / v. Substitute it all in...
Push the nose down a few degrees.
60's a lot. The simulator trials suggest that theoretical optimal is 45, and 35 is probably better for most pilots.
http://www.csgnetwork.com/aircraftturninfocalc.html says that at 60 knots, with a 45 knot stall speed, and a 35 degree angle of bank, you can do a rate 4 turn (180 degrees in 15 seconds), increasing the stall speed to 50 knots. If your VSI is reading -600, you've lost 150ft during the turn.
I'm not talking about a turnback at 500ft, I'm talking at a turnback when I only have 1500ft of runway left. If I'm at 300ft at YWOL, I'm going to land straight ahead because there should be 3500ft of runway left if I've done the takeoff right, so I'm going to land straight ahead At 700ft, landing straight ahead on remaining runway is no longer an option but the turnback should be an option at this point, _ I think_. These numbers differ between aircraft and runways, of course.
(I'm usually at about 800ft at the end of the runway when doing a climb at 80 knots, which is a sort of performance climb situation; 15 faster than BROC).
I was asking about the aerodynamics of the stall in this situation, not the numbers on the instruments. I've not flown anything heavier than a Warrior.